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# Jim and Jesse's Money

## Task

Jim and Jesse each had the same amount of money. Jim spent $\$58$ to fill the car up with gas for a road-trip. Jesse spent $\$37$ buying snacks for the trip. Afterward, the ratio of Jim’s money to Jesse’s money is $1:4$. How much money did each have at first?

## Solutions

Solution: Use two bar diagrams

We know that Jesse has \$21 more than Jim after they make their purchases, because Jim spent \$21 more than Jesse. Since the ratio of money they have remaining is $1:4$, we know this difference is 3 times what Jim has left.

$3 \text{ units } = \$58 - \$37 = \$21$

$1 \text{ unit } = \$7$

We should add what Jim has left to what he spent:

$\$58 + \$7 = \$65$

They each had $\$65$ at first.

Solution: Same story, slightly different analysis

We know that Jim spent \$21 more than Jesse, so Jim has \$21 less than Jesse after they make their purchases. Since Jim has only $\frac14$ as much money as Jesse has, the difference between the two amounts is $\frac34$ of the amount of money Jesse has. So 21 is $\frac34$ of the amount of money Jesse has. Therefore, $\frac14$of the amount of money Jesse has is one third of this, or 7. So Jesse has $4 \cdot 7=28$; and since he spent 37, he originally had $28 + 37=65$. So Jim and Jesse each originally had \$65.

## Jim and Jesse's Money

Jim and Jesse each had the same amount of money. Jim spent $\$58$ to fill the car up with gas for a road-trip. Jesse spent $\$37$ buying snacks for the trip. Afterward, the ratio of Jim’s money to Jesse’s money is $1:4$. How much money did each have at first?

## Comments

Log in to comment## Amelia says:

about 2 monthsThis is very difficult for 6th graders. Maybe using dollar amounts that are multiples of 5 or 3 would be easier and students could grasp the concept more readily. That is just my opinion. I love this site!