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Congruent Rectangles
Task
Below is a picture of two rectangles with the same length and width:
 Show that the rectangles are congruent by finding a translation followed by a rotation which maps one of the rectangles to the other.
 Explain why the congruence of the two rectangles can not be shown by translating Rectangle 1 to Rectangle 2.
 Can the congruence of the two rectangles be shown with a single reflection? Explain.
IM Commentary
This task is designed to give students insight into the effects of translations, rotations, and reflections on geometric figures in the context of showing that two figures are congruent. Since the two rectangles are congruent, there must be some sequence of translations, rotations, and reflections which will take Rectangle 1 to Rectangle 2 (and vice versa). In practice, there are many possible ways to show a congruence and this should be emphasized in part (a). Students might be encouraged to work on their own to find a congruence before working on the three parts of this problem. Instead of a translation followed by a rotation, a rotation followed by a translation is also a natural choice. Or the rotation could be replaced with an appropriate reflection (this is more challenging).
Parts (b) and (c) of the problem show that while there is substantial flexibility in choosing rigid motions to show a congruence, there are some limitations. Part (c) requires good geometric intuition and perhaps some experimentation with reflections. The task is most appropriate for instructional purposes.
The figure provided in the stem of the task does not label the vertices of the rectangles, which provides students with an opportunity to choose to label them on their own, allowing them to engage in standard for mathematical practice 6, Attend to Precision. To see an indepth look at how a teacher might guide such a discussion, take a look at the LessonSketch slideshow linked to our illustration of MP 6: Which Angles are Congruent?
Solution

We can do this by choosing a vertex of Rectangle 1 and then translate this to a carefully selected vertex of Rectangle 2 and then follow this with a rotation about the chosen vertex of Rectangle 2. Pictured below are two possibilities for the translation:
Below is the impact of translating by the lower left arrow which moves Rectangle 1 six boxes to the left and five boxes up to what is now labelled rectangle $PQRS$.:
Also labelled in the picture are vertices $O$ and $T$ of Rectangle 2 and the angle measure $a = m(\angle OPS)$. Rotating rectangle $PQRS$ by angle $a$, counterclockwise, will bring ray $\overrightarrow{PS}$ to ray $\overrightarrow{PO}$. Since $\overline{PO}$ is congruent to $\overline{PS}$ this means that the rotation maps $S$ to $O$. We know that $m(\angle SPQ) = 90^\circ$ and $m(\angle OPT) = 90^\circ$. This means that the rotation by $a$ counterclockwise maps ray $\overrightarrow{PQ}$ to $\overrightarrow{PT}$. Since segments $\overline{PQ}$ and $\overline{PT}$ are congruent, this means that $Q$ maps to $T$. The three vertices $O,P,T$ determine Rectangle 2 so this translation followed by a rotation maps Rectangle 1 to Rectangle 2.

A translation can move Rectangle 1 to any other position on the coordinate grid but will not influence the angles its sides make with the grid lines. The lines containing the upper and lower sides of the rectangle will always be parallel to the horizontal lines of the grid while the lines containing the left and right sides of Rectangle 1 will always be parallel to the vertical lines in the grid. Since none of the lines containing sides of Rectangle 2 are parallel to the grid lines, Rectangle 1 cannot be moved to Rectangle 2 with a translation.

The congruence cannot be exhibited with a single reflection. To see this, we can choose a vertex of Rectangle 1. This is done in the picture below where the chosen vertex is denoted by $A$:
A congruence of two rectangles maps vertices to vertices so this means that $A$ would have to map to one of the four vertices of Rectangle 2. Of these four reflections the one which maps Rectangle 1 closest to Rectangle 2 is the one which sends $A$ to $B$. Below is a picture, in red, of the line of reflection which interchanges $A$ and $B$ (the perpendicular bisector of segment $\overline{AB}$) and the image of Rectangle 1 under this reflection, in blue.
Note that folding over a line which makes a $45^\circ$ angle with the horizontal and vertical grid lines interchanges the horizontal and vertical lines of the grid.
Similarly, any reflection that maps vertex $A$ to any of the other four vertices will not work either. So there is no reflection that maps one of the rectangles to the other.
Congruent Rectangles
Below is a picture of two rectangles with the same length and width:
 Show that the rectangles are congruent by finding a translation followed by a rotation which maps one of the rectangles to the other.
 Explain why the congruence of the two rectangles can not be shown by translating Rectangle 1 to Rectangle 2.
 Can the congruence of the two rectangles be shown with a single reflection? Explain.
Comments
Log in to commentJames King says:
over 1 yearWhile this is a very good problem, with a good commentary, it is marred by a serious risk of misinterpretation. The wording of the original task in Part (a) is really problematic. What the instructions literally say is to assume that the two rectangles are congruent and then prove they are congruent. While I am sure this is not the intention of the designers of the activity, this is how the words can be interpreted. And then the task makes no sense. A rewording of the task could resolve this. For example, "given that the rectangles are congruent, there is a sequence of rigid motions that takes one to the other. Show as an example how this can be done by a translation followed by a reflection." Or, alternatively, instead of assuming that the rectangles are congruent, one could assume that the widths are equal and the lengths are equal and prove the rectangles are congruent by exactly the same reasoning stated in the problem solution. This would a good example of how to prove congruence by rigid motions. But the current wording of (a) needs to be changed. There is a lot of confusion abroad about congruence and transformations; this wording could add to the confusion.
Cam says:
over 1 yearAgreed, both with respect to this task and the general confusion with regards to this material. I've adopted your latter suggestion for the wording of the stem, which I think leaves the wording of (a) okay, though I'd be happy to hear more if you disagree. Thanks again.
ckilburn says:
over 4 yearsI used this for a problem of the week. It forced students to really think what reflections, rotations, and translations really are. Plus it gives students more exposure to slope (lines perpendicular to the same line are parallel, or in this case why this example doesn't hold true in this regard, basic use of a protractor, composition of transformations....great problem.
Cam says:
over 4 yearsJust thought I'd note that you can "rate up" tasks in addition to leaving comments. Eventually the site will begin to aggregate the highest voted tasks, so such upvotes will help filter the best tasks to the top.
Michael Nakamaye says:
over 4 yearsThank you for the positive feedback about this problem! If you have interesting student work to share from when you implement the task we would be very happy to have that to post (you could send this to email@illustrativemathematics.org) . We also of course welcome any suggestions for improvements for the problem. Thanks again for taking a moment to share your feedback!