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# Giantburgers

## Task

This headline appeared in a newspaper.

Every day 7% of Americans eat at Giantburger restaurants |
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Decide whether this headline is true using the following information.

- There are about $8\times 10^3$ Giantburger restaurants in America.
- Each restaurant serves on average $2.5\times10^3$ people every day.
- There are about $3\times10^8$ Americans.

Explain your reasons and show clearly how you figured it out.

## Solution

If there are about $8\times 10^3$ Giantburger restaurants in America and each restaurant serves about $2.5\times10^3$ people every day, then about $$8\times 10^3 \cdot 2.5\times10^3 = 20 \times 10^6 = 2 \times 10^7$$ people eat at a Giantburger restaurant every day.

Since there are about $3\times10^8$ Americans, the percent of Americans who eat at a Giantburger restaurant every day can be computed by dividing the number of restaurant patrons by the total number of people: $$2 \times 10^7\div 3\times10^8 = \frac23 \times 10^{-1}$$ Since $$\frac23 \times 10^{-1} = \frac23 \times \frac{1}{10} = \frac{2}{30} = \frac{1}{15} = 0.06\overline{6},$$ our estimate is that $6\frac23 \%$ of Americans eat a Giantburger restaurant every day, which is reasonably close to the claim in the newspaper.

## Giantburgers

This headline appeared in a newspaper.

Every day 7% of Americans eat at Giantburger restaurants |
---|

Decide whether this headline is true using the following information.

- There are about $8\times 10^3$ Giantburger restaurants in America.
- Each restaurant serves on average $2.5\times10^3$ people every day.
- There are about $3\times10^8$ Americans.

Explain your reasons and show clearly how you figured it out.

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