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Mile High
Task
Denver, Colorado is called “The Mile High City” because its elevation is $5280$ feet above sea level. Someone tells you that the elevation of Death Valley, California is $282$ feet.
 Is Death Valley located above or below sea level? Explain.
 How many feet higher is Denver than Death Valley?
 What would your elevation be if you were standing near the ocean?
IM Commentary
The first two parts of this task ask students to interpret the meaning of signed numbers and reason based on that meaning in a context where the meaning of zero is already given by convention. In 7th grade, students will be asked to connect this reasoning to finding the difference of signed numbers, but they are not expected to know how to add and subtract signed numbers in 6th grade.
The third part is meant as a discussion point about what, exactly, "sea level" means, and will require teachers either to supply more information about the meaning of sea level or to encourage students to research this. Since the oceans have tides, sea level is defined to be the average height of the ocean surface (and is technically called mean sea level). As a result, it is possible to be standing at the edge of the water and be at a negative elevation if the tide is low. The first two parts of the task are straightforward; the third part could provide a good tiein to a science lesson.
Solution

Death Valley is located below sea level. We know this because its elevation is negative. Sea level is the base for measuring elevation. Sea level elevation is defined as 0 ft. All other elevations are measured from sea level. Those places on Earth that are above sea level have positive elevations, and those places on Earth that are below sea level have negative elevations. Thus, Death Valley, with an elevation of 282 feet, is located below sea level.

To find out how much higher Denver is than Death Valley, we can reason as follows:
Death Valley is 282 feet below sea level. Denver is 5280 above sea level. So to go from Death Valley to Denver, you would go up 282 feet to get to sea level and then go up another 5280 feet to get to Denver for a total of $$282+5280 = 5562.$$ feet. Thus, Denver, Colorado is 5562 feet higher than Death Valley, California.

If you were standing near the ocean, your elevation would be close to zero. Depending on how high or low the tide is and where exactly you are standing, your elevation could be as low as 50 feet (or as high as 50 feet) if you are at the edge of a very low tide (or a very high tide, respectively) at the Bay of Fundy.
Mile High
Denver, Colorado is called “The Mile High City” because its elevation is $5280$ feet above sea level. Someone tells you that the elevation of Death Valley, California is $282$ feet.
 Is Death Valley located above or below sea level? Explain.
 How many feet higher is Denver than Death Valley?
 What would your elevation be if you were standing near the ocean?
Comments
Log in to commentNEB says:
over 6 yearsPlease help me understand the solution shown in part b. The methodology seems more than the intent I understand from 6.NS.C.5. The solution of "5280(282) = 5280+282=5562..." asks students to perform operations, not just represent quantities in context. I thought the work shown fits better with 7.NS.1.c.(Understand subtraction of rational numbers as adding the additive inverse, p – q = p + (–q). Show that the distance between two rational numbers on the number line is the absolute value of their difference, and apply this principle in realworld contexts.) If the above is correctly aligned, can you tell me the difference in these two standards, please?
Kristin says:
over 6 yearsThanks for your careful reading of the standards and this task. I agree that a formal approach that identifies the difference in elevation with the difference of signed numbers is not the intent of this standard.
Since students in 6th grade could answer the question just by reasoning about the meaning of the numbers in the context, I changed the solution to one that reflects this type of reasoning but does not formally tie it to arithmetic with signed numbers, which fits in much better with the intent of this standard. I've also changed the commentary to point out this subtle nuance.
Thanks again!